WAEC Mathematics Questions and Answers – 2019 May/June Expo

West Africa Examination Council, WAEC Mathematics Questions and Answers for 2019 May/June Examination is now available.
WAEC Mathematics Questions and Answers

ATTENTION:- PLEASE NOTE THAT SUBSCRIBERS GET ANSWERS BEFORE THE EXAM, ALWAYS SUBSCRIBE FOR EARLY ANSWERS.

👑 2019 WAEC GCE MATHEMATICS ANSWERS👑

100% VERIFIED MATHEMATICS OBJ ANSWERS

1-10: CABDBADCBC
11-20: BCBCBBAACD
21-30: BCCBCCABBA
31-40: AABDDCDDCC
41-50: BBCDCCACCD

100% VERIFIED MATHEMATICS THEORY ANSWERS

(1a)
110x = 40s
Converting both sides to base 10, we have;
(1xX²)+(1xX¹)+(0×X^0) = (4×5¹) + (0×5^0)
X² + X + 0 = 20 + 0
X² + X – 20 = 0
X² + 5x – 4x – 20 = 0
X(x+5)-4(x+5) = 0
(x-4)(x+5) = 0
Since X must be positive
X – 4 = 0
X = 4

(1b)
15/√75 + √108 + √432
= 15/√25×3 + √36×3 + √144×3
=15/5√3 + 6√3 + 12√3
= 3/√3 + 18√3
=3√3/3 + 18√3
= √3 + 18√3
= 19√3
CLICK HERE FOR IMAGE
===================================

(2a)
The equation of the line through the points
A(-2,7) and B(2,-3)
Using the equation Y=mx+b
Where m=slope of the gradient, b=the intercept at the vertical axis
Hence slope=Change in Y/Change in X
=>Y2-Y1/X2-X1=Y-y1/X-x1
=(-3-7)/(2–2)=Y-7/X+2
=-10/4=(Y-7)/(X+2)
=4(y-2)=-10(x+2)
4y-28=-10x-20
4y=-10x+8
5x+2y=4

(2b)
(5b-a)/(8b+3a)=1/5
5(5b-a)=1(8b+3a)
25b-5a=8b+3a
25b-8b=3a+5a
17b=8a
Therefore a/b=17/8
CLICK HERE FOR IMAGE
====================================

(3a)
Ali : Masah : Yusuf = #420,000
3 : 5 : 8
Sum of ratio shared :
3 + 5 + 8 = 16
Therefore
Ali share = 3/16 × 420,000
= #78,750

Musah Share = 5/16 × 420,000
=#131,250

Yusuf share = 8/16 × 420,000
=#210,000

Therefore
Sum of Ali + Yusuf
=#78,750 + #210,000
= #288,750
CLICK HERE FOR IMAGE
====================================

(4)
Since Using Pythagoras theorem
|PR|² = |PQ|² + |QR|²
|PR|² = 3² + 4²
|PR|² = 9 + 16
|PR|² = 25 PR = √25
|PR| = 5cm
Considering PRS
|PS|² = |PR|²+|SR|²
13² = 5² + |SR|²
169 = 25 + |SR|²
|SR|² = 169 – 25
|SR|² = 144
|SR| = √144 = 12cm

Hence the area of the quadrilateral = Area of triangle PQR + area of PRS
= 1/2bh + 1/2bh
= 1/2×4×3 + 1/2×12×5
= 6+30 = 36cm
CLICK HERE FOR IMAGE
====================================
(5a)
No of red balls = 3
No of green balls = 5
No of blue balls = x
Prob.(red ball) = no of total outcome/no of possible outcome
Pr(red) = 3/3+5+x = 1/6
3/8+x = 1/6
6(3) = 1(8+x)
18 = 8 + x
X = 18 – 8 = 10
Therefore the no of blue ball = 10

(5b)
Probability of picking a green ball
P(g) = no of green balls/no of possible outcome
P(g) = 5/3+5+10 = 5/18
=5/18
CLICK HERE FOR IMAGE
==================================

(6ai)
F α M1M2/d²
F = KM1M2/d²
Given F = 20N, M1= 25kg, M2 = 10kg and d = 5m
20 = k(25)(10)/5²
250k = 500
k = 500/250 = 2
Expression is
F = 2M1M2/d²

(6aii)
Making d subject
d = √2M1M2/F
d = √2 ×7.5×4/30
d = √60/30 = √2
d = √2m or 1.41m

(6b)
Draw the diagram
X+X+60+X+80+X+40+X+20 = 540(sum of angles in a Pentagon)
5x + 200 = 540
5x = 540 – 200
5x = 340
X = 340/5
X = 68
CLICK HERE FOR IMAGE
================================

Reader Also Read:  WAEC Agric Practical Questions and Answers – 2019 May/June Expo

(8a)
1/3x – 1/4(x+2)>_ 3x -1⅓
1/3x – 1/4(x+2)>_3x – 4/3
Multiply through by the L. C. M(12), we have
4x – 3(x + 2)>_36x – 16
4x – 3x – 6 >_ 36x – 16
-6+16 >_36x + 3x – 4x
10 >_ 35x
35x _< 10
X = 10/35
X = 2/7

(8bi)
Draw the triangle
|AB|/66 = sin35
|AB| = 66sin35 = 66×0.5736 = 37.8576

Draw the right angled triangle
|AD|/|AB| = Tan52
|AD| = 37.8576 × Tan52° = 37.8576 × 1.2799 = 48.45m
Height of tower = 48.45m

(8bii)
|AC|/66 = Cos35°
|AC| = 66 x cos35°
= 66 x 0.8192
= 54.0672

Tan = 41.86°
Angle of elevation of top of tower from c = 41.85°
CLICK HERE AND HERE FOR IMAGE
==================================

(10)
130kg of tomatoes for #52,000
Half of the tomatoes
130/2 = 65kg sold at 30%
Profit = #52,000/2 = 26,000
#26,000 = 100%
X = 130%
X = 26000 × 130/100
= #33,800

Then 65kg was then sold at reduction of 12% per kg
Recall that the initial cost price = 52000/130
=400kg
65kg sold at = 33,000/65
=#520/kg
Then for 12% reduction
520 × 88/100 = 457.6/kg
(a)
The new selling price per kg = #457.6/kg

(b) 65kg – 5kg = 60kg
(60kg×457.6kg)+33,800
= #61,256.00

#profit = selling price /cost price × 1000/1
=61256/52000×100/1= 117.8
= 17.8%
CLICK HERE FOR IMAGE
================================

(11ai)
ar² = 1/4 ……(1)
ar^5= 1/32 …..(2)
Divide eqn (2) by eqn(1)
ar^5/ar² = 1/32÷1/4
r³ = 1/32 × 4/1
r³= 1/8
r³ = 2-³
r = 2-¹
r = 1/2
Common ratio = 1/2
Put this into eqn (1)
a(1/2)² = 1/4
a(1/4) = 1/4
a = (1/4)/(1/4) = 1
First term, a = 1

(11aii)
Seventh term, T7 = ar^6
=(1)(1/2)^6
=1/64

(11b)
Given : X = 2 and X = -3
(X – 2)(X + 3) = 0
X² + 3x – 2x – 6 , 0
X² + x – 6 = 0
Comparing with ax²+bx+c = 0
a = 1
b = 1
C = -6
CLICK HERE FOR IMAGE
===============================

(12a)
Given : siny = 8/17
Draw the right angle
From Pythagorean triple, third side is 15
Draw the right angle triangle
tan y = 8/15

tan y/1+2tany = 8/15/1+2(8/15) = 8/15/1+16/15

tany /1+2tan y = 8/31

(12b)
Amount shared = #300,000
Otobo’s share = #60,000
Ade’s share = 5/12 × #(300,000-60,000)
= 5/12 × #240,000
=#100,000

Adeobi’s share = #300,000 – (#60,000 + #100,000)
= 300,000 – 160,000
=#140,000

Ratio : Otobo : Ade : Adeola
60,000 : 100,000 : 140,000
60 : 100 : 140
6 : 10 : 14
3 : 5 : 7
CLICK HERE FOR IMAGE

======COMPLETED======

Don’t Just Copy Alone, Drop your Comments, Share with your friends on Facebook & Twitter Using the below share buttons and like our Facebook fan pages Here
BEST OF LUCK

We Update Our Social Media Platform With Latest Updates, Don’t Miss Out Join US On Facebook and For Latest Updates.

Be the first to comment

Leave a Reply

Your Phone Number will not be published.




This site uses Akismet to reduce spam. Learn how your comment data is processed.