2019 WAEC GCE Mathematics Questions and Answers

West Africa Examination Council, WAEC GCE Mathematics Questions and Answers for 2019 June/July Examination are now available, always subscribe to get the already available questions and answers by Examrelief an hour before each paper.

WAEC GCE Mathematics Questions and Answers

ATTENTION:- PLEASE NOTE THAT OUR SUBSCRIBERS GET ANSWERS AN HOUR BEFORE EACH PAPER, ALWAYS SUBSCRIBE FOR EARLIER ANSWERS.

👑 2019 WAEC GCE MATHEMATICS ANSWERS👑

 

100% VERIFIED MATHEMATICS OBJ ANSWERS

1-10: BBDCCBCBBA
11-20: BCBDCDBDDB
21-30: BCBDDBAACA
31-40: AABBDABCCB
41-50: BBBDBCBCDB

100% VERIFIED MATHEMATICS THEORY ANSWERS

(1a)
Table for multiplication (x) in mod 8
Using (2, 3, 5, 7)

In a tabular form.
Under (x) 2, 3, 5, 7
Under 2 4, 6, 2, 6
Under 3 6, 1, 7, 5
Under 5 2, 7, 1, 3
Under 7 6, 5, 3, 1

(1bi)
3(x)n = 5
3 × n = 5 + cont. Of mod 8 to be divisible by 3;
3n = 5 + 8 + 8
3n = 21
n = 21/3
n = 7

(1bii)
n(x)n = 1
n * n = 1 + 8
n² = 9
n = √9
n = 3
CLICK HERE FOR IMAGE
=============================

(2a)
Given; slant height l = 18.7cm
Diameter, d = 24cm
π = 22/7
But, Curved surface area of cone = πrl
=π(d/2)l
= 22/7 × 24/2 × 18.7
=9873.6/14 = 705cm²

(2b)
128^x × 2/16^(1-x) = 8⅔x
= 2^7x × 2/2^4(1-x) = 2³(⅔x)
= 2^7x + 1/2^4(1-x) = 2^2x
Cross multiply
2^4(1 – x) + 2x = 2^7x + 1
4(1 – x) + 2x = 7x + 1
4 – 4x + 2x = 7x + 1
4 – 2x = 7x + 1
9x = 3
X = 3/9 = 1/3
CLICK HERE FOR IMAGE
======================

(3a)
3√3/2 – 4√2/3 – √24
=3√3/2 – 4√2/√3 -√6*4
=(3√3/√2 × √2/√2) – (4√2/√3 × √3/√3) – 2√6
=3√6/2 – 4√6/3 – 2√6
=(3/2 – 4/3 – 2)√6
=(9 – 8 – 12)√6
= -11/6√6

(3bi) prob(only one passes) = m passes and N fails or M fails and N passes
Prob (M passes) = 2/3; prob(M fails) = 1 – 2/3 = 1/3
Prob(N passes) = 4/5; prob(N fails) = 1 – 4/5 = 1/5
Prob(only one passes) = (2/3 × 1/5) + (1/3 × 4/5)
= 2/15 + 4/15
= 6/15
= 2/15

(3bii)
prob(at least one passes) = prob(only one passes) + prob(both parties)
= 2/5 + (2/3 × 4/5)
= 2/5 + 8/15
= 6/15 + 8/15
= 14/15
CLICK HERE FOR IMAGE
===========================

(4a)
17²=X²+15²
17²=X²+225
289-225=X²
64=X²
C=√64=8
Tanθ=18/15
Tanθ/1+2tanθ=18/15/1+2(8/15)=8/15/1+16/15
=8/15÷31/15=8/15*15/31=8/31

(4b)
Log10 y/log10 64 = 1/2
Cross multiply
2log y = log10 64
Log10 y² = log10 64
y = √64
y = ±8
A. CLICK HERE FOR IMAGE
B. CLICK HERE FOR IMAGE
===========================

(5a)
Obtuse Reflex
Obtuse Obtuse = 164°

OMP + OPM + Obtuse MOP = 180°(angles in a triangle)
But OMP = OPM = x(radius of the circle and hence base angles are the same)

2x + 164 = 180
2x = 180 – 164
2x = 16°
X = 16/2 = 8°

Also MNP = 1/2×obtuseMOP
= 1/2 × 164°
= 82°

Now; MNP + NMP + NPM = 180° (angles in a triangle)
82 + (52+8) + (m+8) = 180°
m + 150 = 180°
M = 180 – 150
M = 30°

(5b)
Portion of land for cassava = 2/5
Portion of land for plantain = 1/3 × (1 – 2/5)
= 1/3 × 3/5
= 1/5

Reader Also Read:  WAEC GCE Free Government Questions and Answers – 2019 Second Series Expo

Portion of land for yam = 1 -(2/5 + 1/5)
1 – (3/5)
=2/5
CLICK HERE FOR IMAGE
(5b)
CLICK HERE FOR IMAGE
============================

(6)
a. CLICK HERE FOR IMAGE
b. CLICK HERE FOR IMAGE
=================================

(8ai)
a + 4d = 11 …..i
a + 7d = 20 …. ii

a + 7d = 20
– a + 4d = 11
3d = 9

d = 9/3
d = 3
Using eqn i
a + 4(3) = 11
a + 12 = 11
a = 11 – 12
a = -1

T12 = a + 11d
= -1 + 11(3)
= -1 + 33
= 32

(8aii)
Sn = n/2[20 +(n – 1)d]

S12 = 12/2[2(-1)+(12-1)3]
=6[-2 + (11)3 ]
= 6[-2 + 33]
= 6[31]
= 1806

(8b)
Let the S.p = M
15% of m = 15m/150
= 3m/20 (Discount)

Therefore; collected = M -3m/20
So M/1 – 3M/20 =36000/1
20m – 3m = 720000
17m = 720000
m = 720000/17
M = 42352.94%

Discount = 42352.94 × 3/20
Discount = #6,352.94
CLICK HERE and HERE FOR SNAPPED ANSWERS
===================================

(9ai)
Draw the Venn diagram

(9aii)
No selected for biology but neither physics nor mathematics = 36

(9aiii)
No not selected for any of three subjects = 11

(9b)
Mean = 22+18+(2x+1)+10+20/5 = 15
2x + 71 = 75
2x = 75 – 71
2x = 4
X = 4/2 = 2

The numbers are: 22, 18, 5, 10 and 20
Arranging in ascending order, we have 5, 10, (18), 20, 22

The median is 18

CLICK HERE FOR IMAGE
================================

(10a)
Loan borrowed = 80/100 × 350,000
=280,000
Amount paid to the bank after 8 years = P + I
= P + PRT/100
=280000 + 280000×7×8/100
=280,000 + 156,800
Amount = #436,800

Total cost of house to the man = #350,000 + Interest
= #350,000 + 156,800
= #506,800

(10b)
Percentage increase in cost of house = 506,800 – 350,000 × 100%
= 156,800/350,000 × 100%
= 44.8%

(c) Percentage loss = loss/cost price × 100%
=(506,800 + 10,000) – 460,000/(506,800 + 10,000) × 100%
= 516,800 – 460,000/516,800 × 100%
56,800/516,800 × 100%
= 0.1099 × 100%
= 10.99%
CLICK HERE FOR IMAGE
=====================================

(12)
CLICK HERE FOR IMAGE
====================================

(13a)
Draw the diagram

(i) Extend DO to touch AB at M
AOD + AOM = 180°( 130 + AOM = 180°
AOM = 180 – 130 = 50°

Also;
BMO = BAO + AOM(Ext < = sum of two opposite interior BMO = 26 + 50 = 76°
Also; ABD = 1/2AOD(angle at centre = twice angle at circum)
ABD = 1/2 × 130
=65°
Hence ODB + ABD + BMO = 180°(sum of ODB + 65° + 76° = 180°
ODB = 180 – 141
= 39°

(ii) BOD + ODB + DBO = 180°(sum of But ODB = DBO(base angles of an isosceles triangle)
BOD + 39° + 39° = 180°
BOD + 78° = 180°
BOD = 180 – 78 = 102°

(13b)

|1 2 6

3|1,3 2,3 (6,3)
4|1,4 2,4 (6,4)
5|1,5 2,5 (6,5)

prob (greater than 7) = 3/9 = 1/3
CLICK HERE FOR IMAGE

=====COMPLETED=====

Don’t Just Copy Alone, Drop your Comments, Share with your friends on Facebook & Twitter Using the below share buttons and like our Facebook fan pages Here
BEST OF LUCK

We Update Our Social Media Platform With Latest Updates, Don’t Miss Out Join US On Facebook and For Latest Updates.

4 Comments

Leave a Reply

Your Phone Number will not be published.




This site uses Akismet to reduce spam. Learn how your comment data is processed.