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👑 2019 NECO GCE PHYSICS PRACTICAL ANSWERS👑
100% VERIFIED PHYSICS PRACTICAL ANSWERS
S/N|M(g)|Real values of b(cm)|Converted values of b(cm)| Real Value of d(cm)| Converted values of d(cm)| N = b/d
1 |20 |5.30|26.50|12.9|64.5|0.41|
2 |40 |8.0 |40.0 |10 |50.0|0.80|
3 |60 |9.9 |49.5 |8.3|41.5|1.20|
4 |80 |11.0|55.0 |7.0|35.0|1.50|
5 |100|12.1|60.5 |6.0|30.0|2.0|
Slope = Y2-Y1/X2-X1
(i) I avoid error due to parallel when taking all my reading
(ii) I made sure that the meter rule balanced horizontally before taking my reading
(i) The total upward force must balance the downward.
(ii) The algebraic sum of all forces act on the body must be equal to zero.
If sum of moments of all forces must be zero
.:. 20g x 45cm = 100g x Xcm
X = 20g c 45cm / 100g
1 | 1.0|1.21|1.80|1.49|1.00
2 | 2.0|1.50|1.50|1.00|0.50
3 | 3.0|1.64|1.36|0.83|0.33
4 | 4.0|1.72|1.29|0.75|0.25
5 | 5.0|1.76|1.23|0.70|0.20
PLOT THE GRAPH
Slope = ΔA/V / ΔR-¹
= 1.28 – 0.80/ 0.80 – 0.30
Intercept (c) = 0.50
(i) I would ensure I made tight connection before taking my reading.
(ii) I would ensure I noted zero error on the voltmeter and Ammeter
Potential difference is the work done in moving a unit charge from a point in electric field to another. It has the unit of Volt.
V = work done/charge
r = 0.5ohms
I = 1.2A
R = ?
E = 3v
E = I(R+r)
E = IR + Ir
E – Ir = IR
R = E – Ir/I
= 3 – 1.2 × 0.5/1 .2
= 3 – 0.6/1.2
R = 2.4/1.2
R = 2 ohms
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