2018 NECO GCE Physics Practical Questions and Answers

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ATTENTION:- PLEASE NOTE THAT SUBSCRIBERS GET ANSWERS EARLIER BEOFRE THE EXAM.

👑 2018 NECO GCE PHYSICS PRACTICAL ANSWERS👑

100% VERIFIED PHYSICS PRACTICAL ANSWERS
SNAPPED ANSWERS

(1iv) CLICK HERE

(1graph) CLICK HERE

(1avii) CLICK HERE

(1b) CLICK HERE

(3) CLICK HERE

(3 graph) CLICK HERE

(3 con’t) CLICK HERE

TYPED ANSWERS

(1aiv) [ CLICK HERE ]

In a tabular form
Under S/N
1.0, 2.0, 3.0, 4.0, 5.0

Under y(g)
8.00, 10.00, 12.00, 14.00, 16.00

[Under yR(g)= 12.5*y]
100.00, 125.00, 150.00, 175.00, 200.00

Under X(cm)
17.60, 14.00, 11.60, 10.00, 8.70

Under XR(cm) = x * 2
35.00, 28.00, 23.20, 20.00, 17.40

Under L = 70/X
2.000, 2.500, 3.000, 3.500, 4.00

DRAW ANOTHER TABLE OF y(g) and L(cm)
Under y(g)
100.00
125.00
150.00
175.00
200.00

Under L(cm)
2.00
2.50
3.00
3.50
4.00

(1av)
DRAW THE GRAPH [ CLICK HERE ]

(1avi)
Slope(s) = Dy/DL =
y2 – y1/L2 – L1
Where y2 = 175g, y1 = 100g
L2 = 3.5cm, L1 = 2.00cm

Slope(s) = 175 – 100/3.5 – 2

(1avii)
(PICK TWO)
(i)I ensured mass did not touch/rest on the table
(ii)I avoided error due to parallax on metre rule
(iii)I noted zero error on metre rule
(iv)I avoided draught

(1bi)
The principal of moments state that if a body is in equilibrium,then the sum of the clockwise moments about any point on the body is equal to the sum of the anticlockwise moments about the same point

(1bii)
Draw the diagram [CLICK HERE]

Taking moments about point B ie CWM = ACM
(FA*7) = 10*2
7F = 20
7F/7 = 20/7
F = 2.9N
= 75/1.5
= 50g/cm
=====================================

(3a) [CLICK HERE]

In a tabular form
Under S/N
1, 2, 3, 4, 5, 6

Under R(ohms)
5.0, 10.0, 15.0, 20.0, 25.0, 30.0

Under X(cm)
33.00, 49.50, 60.00, 67.00, 71.00, 74.50

Under K = 100 -X(cm)
67.00, 50.50, 40.00, 33.00, 29.00, 25.50

Under Y = x/k
0.4925, 0.9802, 1.5000, 2.0303, 2.4483, 2.9216

(3avi)
DRAW THE GRAPH [CLICK HERE]

(3avii)
Slope
R2 – R1/y2 -y1
= 20 – 5/2.0 – 0.5
= 15/1.5
=10.0 ohms

(3aviii)
(i) I must use a freshly charged accumulator.
(ii) I must take proper readings through my resistance box and potentiometer to avoid error due to parallax

(3bi)
Lost volt is the voltage lost due to the internal resistance of a cell. It is measured in volts.

(3bii)
E = I(R+r)
4 = I(2+0.5)
4 = 2.5I
I = 4/2.5
= 1.6A

=====COMPLETED======

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