2018 JAN/FEB WAEC GCE Chemistry Practical Answers/Expo/Dubs/Runz

2018 JAN/FEB WAEC GCE Chemistry Practical Answers, 2018 JAN/FEB WAEC GCE Chemistry Practical Expo, 2018 JAN/FEB WAEC GCE Chemistry Practical Runz, 2018 JAN/FEB WAEC GCE Chemistry Practical Questions & Answers, 2018 JAN/FEB WAEC GCE Chemistry Practical choke, JAN/FEB WAEC GCE Chemistry Practical Expo, JAN/FEB WAEC GCE Chemistry Practical Runz, JAN/FEB WAEC GCE Chemistry Practical Chock, complete JAN/FEB WAEC GCE Chemistry Practical Expo, verified JAN/FEB WAEC GCE Chemistry Practical Runz, correct JAN/FEB WAEC GCE Chemistry Practical Chock, WAEC First Series Chemistry Alt Practical, WAEC First Series Chemistry Practical Expo, WAEC First Series Chemistry Practical Runz, WAEC First Series Chemistry Practical Questions & Answers, Free WAEC First Series Chemistry Practical Answers, 2018 WAEC First Series Chemistry Practical Expo, Free 2018 JAN/FEB WAEC GCE Chemistry Practical Runz, Free 2018 JAN/FEB WAEC GCE Chemistry Practical Questions & Answers, free 2018 JAN/FEB WAEC GCE Chemistry Practical choke

ATTENTION:- ALWAYS SUBSCRIBE IF YOU NEED EARLY ANSWERS.

? 2018 JAN/FEB WAEC CHEMISTRY PRACTICAL  ANSWERS?

100% VERIFIED CHEMISTRY PRACTICAL  ANSWERS

YOU MAY ALSO LIKE:  WAEC 2017: 100% Verified Computer Science Questions & Answers Now Available Here

1. CLICK HERE

(1ai)
Burrette readings/cm3:|titre 1|titre2|titre3
Final readings |33.20 |49.60 |1.50
Initial readings |16.40 |16.40 |16.65

(1aii)
Average volume of acid used
= 16.40+16.40+16.65(cm3)/3
=49.45cm3/3
=16.48cm3

(1b)
(I) Concentration of Y(OH)2.XH2O in mol/dm3
Using CAVA/CBVB = a/b
CA= 0.025mol/0.25dm3 = 0.1mol
VA = 16.48cm3
CB = ?
VB = 25.00cm3
a = 1mol
b = 2 moles
.:. CAVA/CBVB =a/b
CB = CAVA*B/VB*a
= 0.1 mol/dm3 * 16.48cm3 * 2 moles / 25.00 * 1 mol
CB = 3.296/25
CB = 0.131mol/dm3
================================

2. CLICK HERE

2 )
Test
I . Solution + NaOH in excess
Ii . Solution + NH 3 in excess
Iii . Solution + BaCl + HCl in excess
Iv. Solution + AgNO 3
Observation
I . White gelatinous precipitate soluble in excess NaOH
Ii . White gelatinous precipitate soluble in excess NH 3
Iii . White precipitate formed with BaCl2 which dissolves in excess HCl
iv . White precipitate formed with AgNO 3

(2bi)
The reagent is the aliphatic monocarboxylic acids that contains one carboxyl group per molecule
[CnH2n+1COOH]
(2bii)
It is observed that they are called fatty acids due to some of them are found in natural fats and oil by changing the -e- ending the corresponding alkane to -oic acid
Pls Draw a table: for Ethanedioic acid(Oxalic acid), Cis-butenedioic(Maleic acid) & 2,3 dihydroxybutanedioic acid(tartaric acid)
Under Ethanedioic acid(Oxalic acid):
COOH
|
CooH
Under Cis-butenedioic(Maleic acid):
H-C-COOH
||
H-C-COOH
Under 2,3 dihydroxybutanedioic acid(tartaric acid):
H
|
HO-C-COOH
|
HO-C-COOH
|
H
====================================

YOU MAY ALSO LIKE:  WAEC GCE 2016 (Practical And Physical) Geography Questions & Answers Now Available

3a)
I)Desiccator- usefor preserving moisture sensitive items
ii)Volumetric flasks are used for precise dilutions and preparation of standard solutions.
iii)Glass rod are used to mix chemicals and liquids for laboratory purposes .

3ii)
i)Amphoteric is Al2O3
ii)Neutral oxide is H2O
3iii)
Crystallization

3b.
i. hno3aq to cuco3 solid. a light blue solid,
precipitates is formed
ii. acidified kmno4 to c2h4. c2h4 is oxidized to ethane-1,2-
diol
iii. iodine solution to a paste of unripe plantain. a bluish-black color is produced with iodine

=====COMPLETED=====

Don’t Just Copy Alone, Drop your Comments, Share with your friends on Facebook, Twitter And Google+ Using the below share buttons and like our Facebook fan pages Here and Here
BEST OF LUCK

Be the first to comment

Drop a Comment

Note: Your Comment Might take up to 2 mins to be published.



This site uses Akismet to reduce spam. Learn how your comment data is processed.